High School

At 8:00 AM, an object with a temperature of 100 degrees Celsius is taken outside where the air temperature is 20 degrees Celsius. After 20 minutes, the temperature drops to 60 degrees Celsius. What is the temperature change of the object during this time?

A. 40 degrees Celsius
B. 50 degrees Celsius
C. 60 degrees Celsius
D. 80 degrees Celsius

Answer :

Final answer:

The temperature change of the object when taken outside was 40 degrees Celsius, calculated by subtracting the final temperature from the initial temperature.

Explanation:

The question involves calculating the temperature change of an object when exposed to a different ambient temperature.

Initially, the object was at 100 degrees Celsius and after 20 minutes, it cooled down to 60 degrees Celsius outside where the air temperature was 20 degrees Celsius. To find the temperature change, you subtract the final temperature from the initial temperature. So, it would be 100 degrees Celsius - 60 degrees Celsius = 40 degrees Celsius.

Therefore, the correct answer is A, 40 degrees Celsius. This problem is a straightforward application of basic arithmetic operations, specifically subtraction, to find the difference between the initial and final temperatures of an object.