High School

A 55 kg lead ball is dropped off the top of the Leaning Tower of Pisa. If the initial velocity of the ball is 0 m/s, what is the speed of the ball in m/s after falling 39.1 m?

A) 28.0
B) 19.6
C) 14.0
D) 9.8

Answer :

Final answer:

The speed of the ball after falling 39.1m is 19.6 m/s.

Explanation:

To find the speed of the ball after falling 39.1m, we need to use the equation for the final velocity of an object in free fall: vf = sqrt(2gh) Where vf is the final velocity, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height fallen. Plugging in the values, we get:

vf = sqrt(2 * 9.8 * 39.1) = 19.6 m/s

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