High School

The inductor in this circuit is storing no energy at time \( t = 0 \).

What is the current through the inductor at time \( t = 1 \, \text{ms} \)?

a. 63.2 mA
b. 39.3 mA
c. 28.3 mA
d. 22.1 mA

Answer :

Final answer:

The question entails calculating the current through an inductor at 1 ms without given initial conditions or circuit details. Without these specifics, such as initial current or the circuit's time constant, it's not possible to calculate the exact value of the current.

Explanation:

The question is asking to calculate the current through an inductor at a specified time (1 ms), given that the inductor is initially storing no energy.

To answer this question, one would typically use the formula for an LR (inductor-resistor) circuit, which is I(t) = I0(1 - e-t/τ), where I0 is the initial current, t is the time, and τ is the time constant of the circuit. Without the values such as the initial current or the time constant (τ) of the circuit, we cannot provide the complete calculation.

The current through an inductor at time t = 1 ms can be determined using the formula I(t) = I(0) * e^(-t/τ), where I(t) is the current at time t, I(0) is the initial current, t is the time, and τ is the time constant of the circuit.

Since the inductor is storing no energy at time t = 0, we can assume the initial current is zero. Plugging these values into the formula, we have I(t) = 0 * e^(-t/τ) = 0. Therefore, the current through the inductor at time t = 1 ms is also zero.