Answer :
Final answer:
The hammer was dropped from a height of 1 foot above the ground.
Explanation:
To calculate the height from which the hammer was dropped, we can use the formula v=sqrt(2gh), where v is the initial speed of the hammer, g is the acceleration due to gravity, and h is the height. In this case, the initial speed of the hammer is 8 feet per second, and the acceleration due to gravity is 32 feet/second². Plugging these values into the formula, we get:
8 = sqrt(2 * 32 * h)
Simplifying, we have:
64 = 64h
Dividing both sides by 64, we find that h = 1 foot.
Therefore, the hammer was dropped from a height of 1 foot above the ground.
Answer:
A. 1.0 foot
Explanation:
Given values
v = 8 # speed in feet per second
g = 32 # acceleration due to gravity in feet/second²
# Using the formula v = sqrt(2gh) to find h
# Rearranging the formula to solve for h: h = v² / (2g)
h = v² / (2g) = (8)² / (2*(32))
h = 64 / 64 = 1
The hammer was dropped from a height of 1 foot above the ground.
