High School

A student on a go-cart (with a combined mass of 82 kg) moving at 6.2 m/s collides with a 17 kg cart initially at rest. As a result of the collision, momentum is transferred from the first cart to the second cart. The velocity of the student and cart is 5.22 m/s after the collision. The collision lasts for 0.20 s.

What is the absolute value of the impulse that is delivered to the student and the first cart during the collision?

A) 181.8 kg·m/s
B) 34.18 kg·m/s
C) 97.4 kg·m/s
D) 12.54 kg·m/s

Answer :

Final answer:

The absolute value of the impulse delivered to the student and the first cart during the collision is 9.84 kg·m/s.

Explanation:

To calculate the impulse that is delivered to the student and the first cart during the collision, we can use the impulse-momentum theorem, which states that the impulse delivered to an object is equal to the change in momentum of that object. The change in momentum can be calculated using the equation:

Δp = m1 * (v1f - v1i)

where Δp is the change in momentum, m1 is the mass of the first cart and student, v1f is the final velocity of the first cart and student, and v1i is the initial velocity of the first cart and student. Plugging in the given values:

Δp = 82 kg * (5.22 m/s - 6.2 m/s) = -9.84 kg·m/s

Since the question asks for the absolute value of the impulse, the answer is 9.84 kg·m/s.

Learn more about Impulse and momentum here:

https://brainly.com/question/33449553

#SPJ11

Other Questions