Answer :
Final answer:
To calculate the pH of the mixture, use the equation pH = 14 - pOH. First, calculate the concentration of OH- ions using the volume and concentration of NaOH. Then, find the pOH by taking the logarithm (base 10) of the OH- concentration. Finally, calculate the pH by subtracting the pOH from 14.
Explanation:
The pH of a mixture made by adding 59.4 mL of 0.22 M NaOH(aq) to 98.1 mL of water can be calculated using the equation pH = 14 - pOH. Since NaOH is a strong base, it dissociates completely in water to form OH- ions. We can calculate the pOH by using the concentration of OH- ions and then find the pH by subtracting the pOH from 14.
First, let's find the concentration of OH- ions in the solution. The number of moles of NaOH can be calculated by multiplying its concentration by the volume of NaOH added: 0.22 M * 0.0594 L = 0.01299 mol. Since NaOH is a strong base, it dissolves into one mole of OH- ions for every mole of NaOH. Therefore, the concentration of OH- ions is also 0.01299 M.
Now, let's calculate the pOH by taking the logarithm (base 10) of the OH- concentration: pOH = -log(0.01299) = 1.87. Finally, we can calculate the pH by subtracting the pOH from 14: pH = 14 - 1.87 = 12.13.
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