Answer :
Final answer:
The average velocity of the train's trip is calculated by dividing the total displacement of the journey by total travel time. Considering the displacement as 19.5 km towards East and total time as 23.11 hours, the average velocity turns out to be 0.84 km/h East.
Explanation:
In physics, average velocity is defined as the change in position (displacement) divided by the time of travel. In this problem, first, we need to calculate the total displacement of the train's travel. The train travels 101.2 km East, then 225.9 km West, and finally 144.2 km East. The directions are important here because East and West are opposite directions.
So the total displacement should be calculated as (101.2 km E + 144.2 km E) - 225.9 km W = 19.5 km East.
Next, we calculate the average velocity by dividing the total displacement by the total time. The total time is given as 23.11 hours. Therefore, the average velocity of the train is 19.5 km / 23.11 hours = 0.84 km/h East.
The direction is included because velocity is a vector quantity, which includes both magnitude and direction.
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