High School

Aluminum metal reacts with chlorine gas in a synthesis reaction.

a. Write the balanced equation for this reaction.

b. If 15.2 g of aluminum reacts with 39.1 g of chlorine, identify the limiting reactant.

Answer :

Final answer:

The balanced chemical reaction between Aluminum and chlorine is 2Al + 3Cl2 -> 2AlCl3. Converting the given amounts of Limiting Reactants into moles, we find that aluminum is the limiting reactant in this reaction as it will be used up before chlorine.

Explanation:

The Balanced chemical reaction between aluminum (Al) and chlorine Aluminum react with 3 moles of chlorine to form 2 moles of Aluminum chloride (AlCl3).

To determine the limiting reactant, first, convert the given amounts of reactants into moles. 15.2 g of Aluminum is approximately 0.565 moles (since the Atomic mass of Al is about 27 g/mole), and 39.1g of chlorine is approximately 1.10 moles (considering that the molar mass of Cl2 is about 35.5 g/mole).

From the balanced equation, we can see that the Mole ratio of Al to Cl2 is 2:3. However, the actual mole ratio given in the problem is 0.565:1.10, or roughly 1:2. This means we have less Al relative to Cl2 than required by the balanced reaction. Therefore, aluminum is the limiting reactant in this reaction as it will be used up first.

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