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What is the volume of 39.1 g of lead if its density is 11.35 g/cm³?

Answer :

Final answer:

The volume of 39.1 g of lead is approximately 0.0034 cm³.


Explanation:

To find the volume of lead, we can use the formula:



Volume = Mass / Density



First, we convert the mass of lead from grams to kilograms:




  1. Mass = 39.1 g = 0.0391 kg



Next, we substitute the values into the formula:




  1. Volume = 0.0391 kg / 11.35 g/cm³



We can cancel out the units of grams, and the final volume will be in cubic centimeters (cm³):




  1. Volume ≈ 0.0034 cm³



Therefore, the volume of 39.1 g of lead is approximately 0.0034 cm³.


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