Answer :
Final answer:
To find the smallest integer in a sequence that adds up to a given sum, set up an equation and solve for the unknown integer.
Explanation:
To find the smallest integer, let's assume the first integer is x. Since the three consecutive integers have to be consecutive, the second integer would be x + 1, and the third integer would be x + 2. Adding up these three integers should give us the sum of 192: x + (x + 1) + (x + 2) = 192. Simplifying the equation, we get 3x + 3 = 192. Solving for x, we find that x = 63. Therefore, the smallest integer is 63.
Learn more about Consecutive integers here:
https://brainly.com/question/35707212
To find the smallest integer among three consecutive integers whose sum is 192, we can set up an equation and solve for the smallest integer.
Let's assume the smallest integer is x.
Since the integers are consecutive, the next two integers would be x+1 and x+2.
The sum of the three consecutive integers is given as 192, so we can write the equation:
x + (x+1) + (x+2) = 192
Simplifying the equation, we get:
3x + 3 = 192
Subtracting 3 from both sides:
3x = 189
Dividing both sides by 3:
x = 63
Therefore, the smallest integer among the three consecutive integers whose sum is 192 is 63.
So, the correct answer is D) 63
