Answer :
Final answer:
The probability that a single randomly selected value is greater than 208 in a normal distribution can be found using the z-score formula. The probability in this case is approximately 0.449.
Explanation:
To find the probability that a single randomly selected value is greater than 208 in a population with a normal distribution, we can use the z-score formula.
z = (x - μ) / σ
Plugging in the values, we get z = (208 - 213) / 39.1 = -0.128.
Using a z-table, we find that the probability corresponding to a z-score of -0.128 is approximately 0.449. Therefore, the probability that a single randomly selected value is greater than 208 is approximately 0.449.
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