High School

Divide 62 into two parts such that one-fourth of the first part and two-fifths of the second part are in the ratio 2:3. Find the first part.

Answer :

Final answer:

To divide 62 into two parts in a specific ratio, we can set up an equation and solve for the first part.

Explanation:

To solve this problem, let's assume the first part of 62 is represented by x. Then, the second part would be 62 - x.

The problem tells us that one fourth part of the first (x/4) and two-fifths part of the second (2/5 * (62 - x) ) are in the ratio 2:3.

We can write the equation: x/4 : (2/5 * (62 - x)) = 2 : 3

We can cross multiply and solve for x to find the value of the first part.

Given two parts add up to 62 and are in the ratio 2:3 when one is divided by 4 and the other by 5, we can determine the first part is 24.

Let's say the two parts we are looking for are a and b. Hence, a + b = 62 (since the two parts add up to 62). If 1/4 part of the first and 2/5 of the second are in the ratio 2:3, this translates into: 1/4a : 2/5b = 2 : 3. Simplifying this, it becomes 5a : 8b = 2 : 3. Now you have two equations that you can solve simultaneously:

  • a + b = 62
  • 5a : 8b = 2 : 3

Solving these equations will give you the values for a and b. In this case, a turns out to be 24 and b turns out to be 38. So the first part is 24.

Learn more about Simultaneous Equations here:

https://brainly.com/question/31913520

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