Answer :
Final answer:
The magnitude of the net gravitational force exerted by the 195-kg and 495-kg objects on the 61.0-kg object is 3.21x10^4 N.
Explanation:
The net gravitational force exerted by the 195-kg and 495-kg objects on the 61.0-kg object can be found using Newton's Law of Universal Gravitation. The formula for gravitational force is F = (G * M1 * M2) / R^2, where G is the gravitational constant, M1 and M2 are the masses of the two objects, and R is the separation distance between them. Plugging in the values, we get:
F = (6.67x10-11 Nm²/kg² * 195 kg * 495 kg) / (3.20 m)^2 = 3.21x104 N.
Therefore, the magnitude of the net gravitational force exerted by these objects on the 61.0-kg object is 3.21x104 N.
Learn more about Newton's Law of Universal Gravitation here:
https://brainly.com/question/38977443
#SPJ11
