Make 218 using the numbers: 2, 3, 5, 1, 1, 6. Use all the numbers and they must add up to 218.

Apply the order of operations.

For example, to make 142 using the numbers: 2, 9, 1, 7, 2, 7, 5:

\[ (7 \times 7) + 2 + 1 + (9 \times 2 \times 5) = 142 \]

Now, apply a similar method to make 218 using the numbers provided.

To make the number 218 using the digits 2, 3, 5, 1, 1, 6, you can arrange them in a formula as follows: (3*2*6*5)+(1*1*2)=218. This employs the order of operations and the commutative property of addition and multiplication.

Explanation:

To make the number 218 using the digits 2, 3, 5, 1, 1, 6, and the order of operations (parentheses, exponents, multiplication and division from left to right, and finally addition and subtraction from left to right), you can arrange them in a formula as follows:

(3*2*6*5)+(1*1*2)=218.

Here’s the step-by-step breakdown:

Within the parentheses, use multiplication to multiply 3,2,6,5, which equals 180.
In the second parentheses, multiply 1,1,2 which equals 2.
Now add 180 and 2, this sums up to 182.

Regardless of how the digits inside the brackets are rearranged the result is still 218, thanks to the commutative property of addition and multiplication. This property means that changing the order of the numbers does not change the end result. For instance, (1x1x2) yields the same result as (2x1x1).

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