High School

A 98% confidence interval was constructed to estimate the awerage weight of US residents and found to be between 195 pounds and 250 pounds. What would be the margin of error for this interval? 27.5 55 222.5 1.645

Answer :

Final answer:

The margin of error for the given confidence interval, representing the average weight of US residents, is calculated by subtracting the lower limit of the confidence interval from the upper limit and dividing the result by 2. Therefore, the margin of error is 27.5 pounds.

Explanation:

The question relates to the calculation of the margin of error in a confidence interval, a concept in statistics. In the given problem statement, a 98% confidence interval was constructed to estimate the average weight of US residents and was found to be between 195 pounds and 250 pounds. The margin of error is the range of values below and above the sample mean in a confidence interval.

To calculate the margin of error, we subtract the lower limit of the confidence interval from the upper limit and then divide the result by 2. So, in this scenario, we subtract 195 from 250 to get 55. We then divide 55 by 2 to get 27.5. So, the margin of error for this interval is 27.5 pounds.

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