Answer :
Final answer:
The equivalent capacitance of the series circuit containing three 83-F capacitors is 27.67 F. The equivalent capacitance is equal to the sum of the reciprocals of the individual capacitances.
Explanation:
To find the equivalent capacitance of the circuit in series.
In this case, you have 3 capacitors each of 83 F.
So, the equivalent capacitance (Ceq) would be calculated as shown:
1/Ceq = 1/C1 + 1/C2 + 1/C3.
Substituting the values, we get 1/Ceq = 1/83 + 1/83 + 1/83 = 3/83.
Therefore, Ceq = 83/3, which simplifies to 27.67 F.
To find the equivalent capacitance of capacitors connected in series, you can use the formula:
1 / C_eq = 1 / C_1 + 1 / C_2 + 1 / C_3 + ...
In your case, you have three 83-µF capacitors connected in series.
So, you can calculate the equivalent capacitance as follows:
1 / C_eq = 1 / (83 µF) + 1 / (83 µF) + 1 / (83 µF)
Now, add these inverses:
1 / C_eq = (1 / 83 + 1 / 83 + 1 / 83) µF^(-1)
1 / C_eq = (3 / 83) µF^(-1)
Now, take the reciprocal of both sides to find C_eq:
C_eq = 83 / 3 µF ≈ 27.67 µF
So, the equivalent capacitance of the circuit is approximately 27.67 µF.
Learn more about Equivalent Capacitance
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