Answer :
Final answer:
The molarity of a 36.2 mg NaCl solution in 118.3 ml of solution is calculated by converting the mass of NaCl to moles using its molar mass, and by expressing the volume in liters, then dividing the number of moles by the volume. The calculated molarity is 0.0053 M.
Explanation:
To calculate the molarity of 36.2 mg of NaCl in 118.3 ml of solution, we first need to convert the mass of NaCl from milligrams to grams, and the volume from milliliters to liters. We find that 36.2 mg of NaCl is equal to 0.0362 grams and 118.3 ml is equal to 0.1183 liters. The molar mass of NaCl is approximately 58.44 g/mol.
Now we use the equation Molarity = moles of solute / volume of solution in liters. Therefore, the molarity = (0.0362 g / 58.44 g/mol) / 0.1183 L = 0.0053 M.
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