Answer :
The largest integer in a sequence of 101 consecutive integers that sum to 101 is 51. This is found by identifying the median (1), and then adding 50 (the count of numbers to the right of the median in the sequence)
In mathematics, when dealing with consecutive integers, the sum of the integers is equal to the number of integers multiplied by the median integer.
The median of these 101 consecutive integers is the integer that makes the sum equals 101.
So, (101 * Median) = 101, which resolves into Median = 1.
Given that there are 101 numbers and that the numbers are consecutive, 50 numbers lie to the left, and 50 to the right of the median (1).
Therefore, the largest integer in this sequence will be Median + 50, which is 1 + 50 = 51.
Hence, 51 is the largest integer in the sequence.
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