Answer :
Final answer:
To calculate the number of gold atoms in 98.5 g of gold, divide the given mass by the molar mass of gold and multiply by Avogadro's number. The number of gold atoms in 98.5 g is approximately 3.011 x 10^23 atoms.
Explanation:
To calculate the number of gold atoms in 98.5 g of gold, we need to use the concept of moles. First, we convert the given mass of gold to moles by dividing it by the molar mass of gold, which is 197 g/mol. So, 98.5 g of gold is equal to 0.5 moles. One mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23 particles. Therefore, 0.5 moles of gold would contain 0.5 x 6.022 x 10^23 gold atoms.
Calculating this value, we get the number of gold atoms in 98.5 g of gold to be 3.011 x 10^23 atoms.
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