Let \( X \) represent the full height of a certain species of tree. Assume that \( X \) is normally distributed with a mean of 232.2 feet and a standard deviation of 59.1 feet. Find the probability that the full height of a randomly selected tree is less than 184.9 feet.

\[ P(X < 184.9) = \]

Enter your answer as a number accurate to 4 decimal places.

To find the probability that the full height of a randomly selected tree is less than 184.9 feet, we need to standardize the value using the z-score formula. The z-score formula is given by Z = (X - μ) / σ, where X represents the value, μ represents the mean, and σ represents the standard deviation. In this case, X = 184.9 feet, μ = 232.2 feet, and σ = 59.1 feet. Plugging in these values, we get Z = (184.9 - 232.2) / 59.1 = -0.795.

To find the probability that the full height of a randomly selected tree is less than 184.9 feet, we use a Z-score. The Z-score represents how many standard deviations an element is from the mean. You can calculate the Z-score using the formula: (X - μ) / σ, where X is the value, μ is the mean and σ is the standard deviation.

To find the probability that the full height of a randomly selected tree is less than 184.9 feet, we use a Z-score. The Z-score represents how many standard deviations an element is from the mean. You can calculate the Z-score using the formula: (X - μ) / σ, where X is the value, μ is the mean and σ is the standard deviation.

To find the probability, we can use a standard normal distribution table or a calculator to look up the corresponding probability for a z-score of -0.795. The probability can be read as P(Z < -0.795). Looking it up, we find the probability to be 0.2146 (rounded to 4 decimal places).

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