Since January 1, 1960, the population of Slim Chance has been described by the formula

\[ P = 29000(0.93)^t \]

where \( P \) is the population \( t \) years after the start of 1960.

At what rate was the population changing on January 1, 1984?

To find the rate at which the population was changing on January 1, 1984, we need to find the derivative of the population function. The derivative represents the rate of change. In this case, the population function is given as P = 29000(0.93)^t. Taking the derivative with respect to t, we get dP/dt = 29000 * ln(0.93) * (0.93)^t.

Now we substitute t = 1984-1960 = 24 into the derivative equation to find the rate at which the population was changing on January 1, 1984.

dP/dt = 29000 * ln(0.93) * (0.93)^24 ≈ -704.41

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Since January 1, 1960, the population of Slim Chance has been described by the formula \[ P = 29000(0.93)^t \]where \( P \) is the population \( t \) years after the start of 1960. At what rate was the population changing on January 1, 1984?

Answer :

Final answer:

Explanation:

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Other Questions

Since January 1, 1960, the population of Slim Chance has been described by the formula

\[ P = 29000(0.93)^t \]

where \( P \) is the population \( t \) years after the start of 1960.

At what rate was the population changing on January 1, 1984?