Assume a simple segmentation system with a maximum segment size of [tex]2^6[/tex]. The segmentation table for process PO is organized by length and base as follows:

- Segment 1: Length [tex]0x10[/tex], Base [tex]0x30[/tex]
- Segment 2: Length [tex]0x20[/tex], Base [tex]0x58[/tex]
- Segment 3: Length [tex]0x08[/tex], Base [tex]0x20[/tex]

When the process addresses location [tex]0x5C[/tex], what physical address is accessed?

Answer :

The physical address accessed would be the sum of the base address (0x58) and the offset within the segment (0x5C - 0x58 = 0x04), resulting in a physical address of 0x5C.

In a simple segmentation system, when the process addresses location Ox5C, the physical address accessed would be 0x5C.

In this question, we are given a simple segmentation system with a maximum segment size of 2^6, and a segmentation table for process PO

. The segmentation table entries consist of pairs of length and base values. The length represents the size of the segment, and the base represents the starting address of the segment in physical memory.

When the process addresses location Ox5C, we need to determine which segment in the segmentation table contains this address. Comparing Ox5C to the base addresses in the table, we find that it falls within the segment with base address 0x58 and length 0x08.

Therefore, the physical address accessed would be the sum of the base address (0x58) and the offset within the segment (0x5C - 0x58 = 0x04), resulting in a physical address of 0x5C.

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