High School

For the following data:

4.9, 5.1, 6.3, 6.7, 7.0, 7.1, 7.8, 8.6, 8.7, 8.8, 8.9, 9.0, 9.4, 9.4, 9.5, 9.6, 9.9, 10.0, 10.1, 10.1, 10.1, 10.3, 10.4, 10.7, 10.9, 11.3, 11.6, 11.8, 14.3

If the 3rd class limit is (8-9.9), then the upper boundary for the 5th class equals:

Select one:

A. 11.95
B. 13.95
C. NONE
D. 13.905

Answer :

The upper boundary for the 5th class can be found by determining the upper limit of the given class interval, which is (8-9.9). The upper boundary for the 5th class is 1.9.

To find the upper boundary, we need to subtract the lower limit of the class interval from the upper limit of the class interval. In this case, the lower limit is 8 and the upper limit is 9.9.

So, the upper boundary for the 5th class can be calculated as follows:

Upper Boundary = Upper Limit - Lower Limit
Upper Boundary = 9.9 - 8
Upper Boundary = 1.9

Therefore, the upper boundary for the 5th class is 1.9.

Conclusion:
The upper boundary for the 5th class, with a class interval of (8-9.9), is 1.9.

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