How many protons, neutrons, and electrons are in the following nuclide symbol: [tex] ^{209}_{83}\text{Bi}^{-3} [/tex]?

A. 83 protons, 129 neutrons, 89 electrons
B. 84 protons, 126 neutrons, 87 electrons
C. 84 protons, 127 neutrons, 86 electrons
D. 83 protons, 126 neutrons, 86 electrons
E. 82 protons, 125 neutrons, 85 electrons
F. 83 protons, 129 neutrons, 86 electrons
G. 83 protons, 123 neutrons, 86 electrons
H. 83 protons, 126 neutrons, 83 electrons
I. 82 protons, 125 neutrons, 86 electrons
J. 84 protons, 126 neutrons, 86 electrons
K. 82 protons, 126 neutrons, 86 electrons
L. 83 protons, 123 neutrons, 83 electrons

The nuclide symbol 20983Bi-3 represents an isotope of the element bismuth. To determine the number of protons, neutrons, and electrons, we can analyze the nuclide symbol:

Number of protons (atomic number) = 83

Number of neutrons (mass number - atomic number) = 209 - 83 = 126

Number of electrons (equal to the number of protons in a neutral atom) = 83

Therefore, the correct answer is: 83 protons, 126 neutrons, and 83 electrons.

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haripriyanath29 haripriyanath29 · Answer 2 · 2023-11-20T17:15:51-05:00

Final answer:

The nuclide symbol 20983Bi-3 represents an isotope of Bismuth with 83 protons, 126 neutrons, and 86 electrons.

Explanation:

A nuclide symbol provides information about the isotope of an element. In the given nuclide symbol, 20983Bi-3, the number 209 represents the mass number, which is the sum of protons and neutrons in the nucleus. The atomic number, 83, represents the number of protons in the nucleus. The superscript -3 indicates a charge of -3, meaning the atom has gained 3 electrons.

Therefore, the number of protons in the nuclide symbol is 83, the number of neutrons is calculated by subtracting the atomic number from the mass number: 209 - 83 = 126, and the number of electrons is determined by the charge: 83 + 3 = 86.

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