Answer :
Final answer:
The balanced molecular equation contains the term b) 2AgCl(s). The balanced complete ionic equation contains the terms a) 2Ag+(aq). The limiting reactant in the reaction between calcium phosphate and sulfuric acid is d) H2SO4. The concentration of the solution formed by dissolving hydrofluoric acid in water is 0.82 M. In the reaction between calcium and oxygen, the species that is oxidized is b) Ca.
Explanation:
To determine the balanced molecular equation, we need to write the chemical equation for the reaction between barium chloride (BaCl2) and silver nitrate (AgNO3). The balanced equation is:
BaCl2(aq) + 2AgNO3(aq) -> 2AgCl(s) + Ba(NO3)2(aq)
The term in the balanced molecular equation is 2AgCl(s).
To determine the balanced complete ionic equation, we need to write the chemical equation with all the ions present in the reaction. The balanced complete ionic equation is:
Ba²+(aq) + 2Cl-(aq) + 2Ag+(aq) + 2NO3-(aq) -> 2AgCl(s) + Ba²+(aq) + 2NO3-(aq)
The terms in the balanced complete ionic equation are 2Ag+(aq)
To determine the limiting reactant in the reaction between calcium phosphate (Ca3(PO4)2) and sulfuric acid (H2SO4), we need to compare the given amounts of reactants to their stoichiometric ratios. The balanced equation is:
Ca3(PO4)2 + 3H2SO4 -> 3CaSO4 + 2H3PO4
Using the given amounts of 129 g of Ca3(PO4)2 and 97.4 g of H2SO4, we can calculate the moles of each reactant:
moles of Ca3(PO4)2 = 129 g / molar mass of Ca3(PO4)2
moles of H2SO4 = 97.4 g / molar mass of H2SO4
By comparing the moles of each reactant to their stoichiometric ratios, we can determine that the limiting reactant is H2SO4.
To calculate the concentration of the solution formed by dissolving 16.4 g of HF in 2.0 x 10² mL of water, we need to convert the mass of HF to moles and the volume of the solution to liters:
moles of HF = 16.4 g / molar mass of HF
volume of solution = 2.0 x 10² mL / 1000 mL/L
Then, we can calculate the concentration:
concentration = moles of HF / volume of solution
The concentration of the solution is 0.82 M.
In the reaction between calcium (Ca) and oxygen (O2), calcium is oxidized. The species that is oxidized is Ca.
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