Answer :
The value of d is 0.26, representing the mean of the differences between temperatures at 8 AM and 12 AM. The standard deviation, sd, is 0.198, indicating the variability of these differences.
To find the values of d and sd, we need to calculate the differences between the temperatures at 8 AM and 12 AM for each subject and then perform some calculations.
Temperature (°F) at 8 AM: 97.6, 99.3, 97.2, 97.3, 97.9
Temperature (°F) at 12 AM: 98.1, 99.7, 97.4, 96.9, 98.2
To calculate d, we subtract the temperature at 8 AM from the temperature at 12 AM for each subject and find the mean of these differences:
d = mean(temperature at 12 AM - temperature at 8 AM)
d = (98.1 - 97.6 + 99.7 - 99.3 + 97.4 - 97.2 + 96.9 - 97.3 + 98.2 - 97.9) / 5
d = 0.5 + 0.4 + 0.2 - 0.4 + 0.2 + 0.1 - 0.4 + 0.3 + 0.3 - 0.1 / 5
d = 1.3 / 5
d = 0.26
So, d = 0.26
To calculate sd (standard deviation), we need to find the standard deviation of the differences between the temperatures at 8 AM and 12 AM. First, we calculate the differences for each subject, then we find the mean of these differences, and finally, we calculate the standard deviation:
sd = standard deviation(temperature at 12 AM - temperature at 8 AM)
Step 1: Calculate the differences:
98.1 - 97.6 = 0.5
99.7 - 99.3 = 0.4
97.4 - 97.2 = 0.2
96.9 - 97.3 = -0.4
98.2 - 97.9 = 0.3
Step 2: Calculate the mean of the differences:
Mean of differences = (0.5 + 0.4 + 0.2 - 0.4 + 0.3) / 5
Mean of differences = 0.2 / 5
Mean of differences = 0.04
Step 3: Calculate the standard deviation of the differences:
sd = sqrt((0.5 - 0.04)^2 + (0.4 - 0.04)^2 + (0.2 - 0.04)^2 + (-0.4 - 0.04)^2 + (0.3 - 0.04)^2) / (5-1)
sd = sqrt((0.46)^2 + (0.36)^2 + (0.16)^2 + (-0.44)^2 + (0.26)^2) / 4
sd = sqrt(0.2116 + 0.1296 + 0.0256 + 0.1936 + 0.0676) / 4
sd = sqrt(0.628) / 4
sd = 0.792 / 4
sd = 0.198
So, sd = 0.198 (rounded to two decimal places).
In general, µd represents:
B. The mean of the differences from the population of matched data
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