High School

Calculate \(\Delta S\) for the vaporization of 0.500 mol of ethanol. The molar heat of vaporization of ethanol is 39.3 kJ/mol, and the boiling point of ethanol is 78.3°C.

Answer :

the heat (enthalpy) for the vaporization of 0.500 mol of ethanol is 19.65 kJ.

To calculate the heat (enthalpy) for the vaporization of 0.500 mol of ethanol, we can use the equation:

ΔH = n × ΔHvap

where ΔH is the heat, n is the number of moles, and ΔHvap is the molar heat of vaporization.

Given:

n = 0.500 mol

ΔHvap = 39.3 kJ/mol

Plugging in the values:

ΔH = (0.500 mol) × (39.3 kJ/mol)

ΔH = 19.65 kJ

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