Answer :
The drag force acting on the oil float in the rotameter is 160.884 x 10^-3 N upwards. This force allows the float to maintain a steady position against the 10 litres/minute mark on the tube.
In a rotameter, the float is subjected to two forces: the buoyant force and the drag force. The buoyant force is equal to the weight of the fluid displaced by the float, and it acts in the upward direction. The drag force, on the other hand, opposes the motion of the float through the fluid.
Given that the float is steady against the 10 litres/minute mark on the tube, we can assume that the buoyant force and the drag force balance each other. The drag force acting on the float is stated as 160.884 x 10^-3 N upwards. This means that the drag force is equal in magnitude but opposite in direction to the buoyant force. The drag force is necessary to counteract the buoyant force and keep the float at a fixed position.
The density of the oil is given as 800 kg/m^3, and the mass of the float is 10 gm (0.01 kg). From these values, we can determine the volume of the float using the formula: density = mass/volume. Rearranging the formula, we find that the volume of the float is 0.01 kg / 800 kg/m^3 = 0.0000125 m^3 (or 12.5 cm^3).
Therefore, the drag force of 160.884 x 10^-3 N upwards is required to balance the buoyant force and maintain the float's position against the 10 litres/minute mark on the tube.
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