Answer :
the partial pressure of CO2 (PCO2) in mm Hg produced by the calibration gas, given a barometric pressure of 747 mm Hg and a water vapor pressure of 47 mm Hg, is approximately 37.35 mm Hg.
To determine the partial pressure of CO2 (PCO2) in mm Hg that would be produced by a calibration gas with a CO2 concentration of 5.0% and a water vapor pressure of 47 mm Hg, we need to consider the total pressure and the partial pressure of water vapor.
The total pressure (Ptotal) is the sum of the partial pressures of CO2 (PCO2) and water vapor (PH2O):
Ptotal = PCO2 + PH2O
Given:
CO2 concentration = 5.0% = 5.0/100 = 0.05 (decimal form)
Water vapor pressure (PH2O) = 47 mm Hg
Barometric pressure = 747 mm Hg
First, we need to calculate the partial pressure of CO2 using the CO2 concentration and the barometric pressure:
PCO2 = CO2 concentration * Barometric pressure
PCO2 = 0.05 * 747 mm Hg
PCO2 = 37.35 mm Hg
Now, we can calculate the total pressure (Ptotal) by adding the PCO2 and PH2O:
Ptotal = PCO2 + PH2O
Ptotal = 37.35 mm Hg + 47 mm Hg
Ptotal = 84.35 mm Hg
Therefore, the partial pressure of CO2 (PCO2) in mm Hg produced by the calibration gas, given a barometric pressure of 747 mm Hg and a water vapor pressure of 47 mm Hg, is approximately 37.35 mm Hg.
Learn more about barometric pressure here:
https://brainly.com/question/30460451
#SPJ11
