High School

After successfully clearing the bar during the pole vault, the vaulter falls to the landing cushion. If his momentum is -980 kg·m/s and he has a velocity of -12.5 m/s just prior to landing, what is the mass of the vaulter?

A. 98.1 kg
B. 980.0 kg
C. 78.4 kg
D. 80.0 kg

Answer :

Answer: The mass of the vaulter is 78.4 kg.

After successfully clearing the bar during the pole vault, the vaulter falls to the landing cushion while trying to calculate the impending impulse which will break his fall.

Momentum = -980 kg.m/s

Velocity = -12.5 m/s

Impulse is the force acting for a specific time and it is given by: Impulse = Momentum = mass × velocity

Impulse = Momentum

Impulse = mass × velocity

mass = Impulse / velocity

Now, substitute the given values of impulse and velocity into the above equation: mass = Impulse / velocity= -980 kg.m/s / -12.5 m/s= 78.4 kg.

Therefore, the mass of the vaulter is 78.4 kg.

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