Answer :
To calculate the molarity (M) of the ammonium sulfate in the solution, The molarity of the ammonium sulfate in the aqueous solution is 0.926 M.
To calculate the molarity (M) of the ammonium sulfate in the solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to determine the number of moles of ammonium sulfate in the solution. We can do this by converting the given mass of ammonium sulfate to moles using its molar mass. The molar mass of ammonium sulfate is approximately 132.14 g/mol.
Number of moles = mass / molar mass
Number of moles = 98.1 g / 132.14 g/mol
Next, we need to convert the given volume of the solution from milliliters to liters:
Volume of solution = 105.6 ml = 105.6 ml / 1000 ml/L = 0.1056 L
Now we can calculate the molarity:
Molarity = moles / volume of solution
Molarity = (98.1 g / 132.14 g/mol) / 0.1056 L
After performing the calculation, the molarity of the ammonium sulfate in the solution is found to be approximately 0.926 M.
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