High School

Problem 4: After reaching the top of the mountain, the parcel above begins to sink. PLEASE READ!!!! FOR PROBLEM #4, YOU ARE GOING TO USE THE TEMPERATURE/DEW POINT OF THE PARCEL FROM PROBLEM 3 AT 3000M... BUT NOW THE PARCEL IS SINKING 1 point What will the parcel's temperature be at 2000 meters (hint: the parcel warms Dry Adiabatically as it sinks). * Your answer 1 point What will the parcel's temperature be at O meters... The Surface (hint: the parcel warms Dry Adiabatically as it sinks). *

Answer :

The initial temperature at 3000 meters was determined in Problem 3, you can substitute that value into the equations above to find the parcel's temperature at 2000 meters and at the surface (0 meters).

To determine the parcel's temperature at 2000 meters and at the surface (0 meters), we can use the dry adiabatic lapse rate, which describes the rate at which the temperature of a parcel changes as it rises or sinks in the atmosphere.

The dry adiabatic lapse rate is approximately 9.8°C per kilometer. This means that for every 1000 meters of ascent or descent, the temperature of the parcel will change by 9.8°C.

Since the parcel is sinking, we know that it will warm at the dry adiabatic lapse rate. Given that the temperature of the parcel at 3000 meters was determined in Problem 3, we can calculate the temperature at 2000 meters and at the surface (0 meters) as follows:

Temperature at 2000 meters:

From 3000 meters to 2000 meters, there is a descent of 1000 meters. Therefore, the temperature change will be 9.8°C * (1000/1000) = 9.8°C.

So, the temperature at 2000 meters will be the initial temperature at 3000 meters + 9.8°C.

Temperature at 0 meters (surface):

From 3000 meters to the surface (0 meters), there is a descent of 3000 meters. Therefore, the temperature change will be 9.8°C * (3000/1000) = 29.4°C.

So, the temperature at the surface will be the initial temperature at 3000 meters + 29.4°C.

Since the initial temperature at 3000 meters was determined in Problem 3, you can substitute that value into the equations above to find the parcel's temperature at 2000 meters and at the surface (0 meters).

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