Answer :
51.2 mL of the 0.330 mm KOH solution contains 1.69×10−2 mol of KOH. we can use the formula:
Volume = (amount of solute) / (molarity)
To calculate the volume of the solution containing a given number of moles of solute, we can use the formula:
Volume = (amount of solute) / (molarity)
Here, the molarity of the KOH solution is 0.330 mm or 0.330 × 10^-3 mol/mL. The amount of KOH in 1.69×10−2 mol is:
Amount of solute = 1.69×10−2 mol
Putting the values in the formula, we get:
Volume = (1.69×10−2 mol) / (0.330 × 10^-3 mol/mL)
Volume = 51.2 mL
Therefore, 51.2 mL of the 0.330 mm KOH solution contains 1.69×10−2 mol of KOH.
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