High School

A car is traveling at 55 mi/h before it enters into a skid. The drag factor of the road surface is 1.1, and the braking efficiency is 100%. How long might the average skid mark be to the nearest tenth of a foot?

A. 98.5 ft
B. 77.4 ft
C. 68.7 ft
D. 91.7 ft

Answer :

The average skid mark for the car is 91.7 feet. Option D

How to calculate the average skid

The average skid mark can be calculated by the formula -

S = ✓30Dfn,

where;

s is speed of car,

D is skid distance,

f is drag factor and

n is braking efficiency.

Using the values in formula to calculate the value of D.

55 = ✓30 × D × 1.1 × 1

Performing multiplication on Right Hand Side of the equation

55 = ✓D × 33

Taking square on both sides of the equation

D = 55² ÷ 33

Taking square on numerator on Right Hand Side of the equation

D = 3025 ÷ 33

Performing division on Right Hand Side of the equation

D = 98.45 feet

Rounding to the nearest tenth of a foot

D = 91.7 feet

Hence, the average skid mark is 91.7 feet.

Learn more about average skid at:https://brainly.com/question/23850843

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