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A jogger jogs from one end to the other of a straight track in 1.03 minutes and then back to the starting point in 1.69 minutes. Assume the track is 100 meters long. What is the jogger's average speed in the following scenarios?

(a) Jogging to the far end of the track (m/s)

(b) Coming back to the starting point (m/s)

(c) For the total jog (m/s)

Answer :

From the information given,

time taken to jog from one end to the other of a straight track is 1.03 min. We would convert the time to seconds by multiplying by 60. Thus,

time taken to jog from one end to the other = 1.03 x 60 = 61.8s

time taken to jog back = 1.69 min = 1.69 x 60 = 101.4s

distance = 100 m

Distance = speed x time

a) distance = 100

time = 61.8s

average jogger'speed = 100/61.8

average jogger'speed = 1.62 m/s

b) distance = 100

time = 101.4

averge speed = 100/101.4

Average speed when coming back to the starting point = 0.99 m/s

c) Total distance = 100 + 100 = 200

Total time = 61.8 + 101.4 = 163.2

Average speed = 200/163.2

Average speed = 1.23 m/s

Average speed =

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