Answer :
1520 N Force she feels "pressing her into the back of the seat."
We have given in the statement :
In horizontal direction,
a = 3 g
a= 3×9.8 m/s^2
a= 29.4 m/s^2
Now using force formula to find the magnitude
F = m×a
F= 51.7 Kg × 29.4 m/s^2
F= 1520 N
- A push or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on each of the objects.
- The force is no longer felt by the two objects after the interaction ends. Only when there is interaction do forces actually exist.
- The standard metric unit known as the Newton is used to quantify force. "N" stands for Newton in abbreviation.
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The fighter pilot experiences a force of 1520.98 Newtons during takeoff, calculated by multiplying the pilot's mass with the acceleration of 3g, which is [tex]29.4 m/s^2[/tex].
The force experienced by a fighter pilot during takeoff can be calculated using Newton's second law of motion, which is expressed as [tex]Force\ (F) = mass\ (m) \times acceleration\ (a)[/tex]. Here, the pilot is exposed to an acceleration of 3g, which is three times the acceleration due to gravity.
Since 1g is [tex]9.8\ m/s^2[/tex], 3g will be [tex]3 \times 9.8\ m/s^2 = 29.4\ m/s^2[/tex]. By substituting the given mass of the pilot, 51.7 kg, into the formula, we get:
[tex]F = m \times a = 51.7\ kg \times 29.4\ m/s^2 = 1520.98\ N[/tex]
Therefore, the force that the pilot experiences is 1520.98 Newtons.
