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An 85 kg skydiver is falling through the air at a constant speed of 195 km/h. At what rate does air resistance remove energy from the skydiver?

Answer :

Final answer:

To calculate the rate at which air resistance removes energy from a skydiver, we need to know the distance traveled by the skydiver.

Explanation:

Analyzing the problem:

The skydiver is falling at a constant speed, which means that the net force acting on the skydiver is zero. Therefore, the force of gravity pulling the skydiver downward is balanced by the force of air resistance pushing upward.

Determining the rate of energy removed by air resistance:

The work done by air resistance is equal to the force of air resistance multiplied by the distance traveled by the skydiver. Energy removed is simply the work done per unit time.

  1. First, we need to calculate the force of gravity acting on the skydiver, which is given by the formula F = m * g, where m is the mass of the skydiver (85 kg) and g is the acceleration due to gravity (9.8 m/s²).
  2. Next, we calculate the force of air resistance. Since the skydiver is falling at a constant speed, the force of air resistance is equal in magnitude to the force of gravity. Therefore, the force of air resistance is also 85 kg * 9.8 m/s².
  3. With the force of air resistance known, we can calculate the work done by air resistance using the formula W = F * d, where F is the force of air resistance and d is the distance traveled by the skydiver. In this case, the distance traveled is not given, so we cannot calculate the exact rate at which energy is removed by air resistance.

Answer:

Unfortunately, without knowing the distance traveled by the skydiver, we cannot determine the rate at which air resistance removes energy. However, we know that the force of air resistance is equal in magnitude to the force of gravity acting on the skydiver.

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Answer:

45167.15 J/s

Explanation:

mass of the man = 85 kg

The man's speed = 195 km/h = 195 x 1000/3600 = 54.167 m/s

The man's weight = mg

where

m is the mass

g is acceleration due to gravity = 9.81 m/s^2

weight = 85 x 9.81 = 833.85 N

The rate at which energy is removed from the man = speed x weight

==> 54.167 x 833.85 = 45167.15 J/s