Answer :
Final answer:
The energy of a single photon at the transmitted frequency of an 11,000-watt radio station at 880 kHz is 5.8 x 10-28 J/photon.
Explanation:
To calculate the energy of a single photon at the transmitted frequency, we can use the formula:
Energy of a photon = Planck's constant x frequency.
Given that the radio station transmits at a frequency of 880 kHz (880,000 Hz) and Planck's constant is approximately 6.63 x 10-34 J s, we can calculate the energy as follows:
- Convert the frequency to Hz: 880 kHz = 880,000 Hz
- Multiply the Planck's constant by the frequency: (6.63 x 10-34 J s) x (880,000 Hz) = 5.8 x 10-28 J/photon
Therefore, the energy of a single photon at the transmitted frequency is 5.8 x 10-28 J/photon.
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Final answer:
The energy of a single photon at the transmitted frequency of an 11,000-watt radio station that transmits at a frequency of 880 kHz can be calculated using the Planck–Einstein relation (E=h*f), where 'h' is Planck's constant and 'f' is the frequency. The answer is 5.8 x 10^-28 J/photon.
Explanation:
To solve this problem, we need to understand the relationship between the energy of a photon, frequency, and Planck's constant. According to the Planck–einstein relation, the energy of a photon (E) can be calculated using the formula E=h*f, where 'h' is Planck's constant and 'f' is the frequency. The value of Planck's constant (h) is approximately 6.626 x 10-34 m2kg/s.
In this question, the frequency (f) of the radio station is given as 880 kHz or 880 x 103 Hz (since 1 kHz = 103 Hz).
Now, we can substitute these values into the equation E=h*f:
E = (6.626 x 10-34) * (880 x 103)
Solving this, we get E = 5.8308 x 10-28 J/photon. So, the answer is 5.8 x 10-28 J/photon.
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